For the tent map or shift map
$|\lambda| = 2$
Dense set of unstable orbits.
Given $x$ and $\epsilon$, there is an unstable orbit in a ball of radius $\epsilon$ centered at $x$.
Periodic points are countably infinite. They are a measure zero set. Hence “all” points are unstable and chaos is typical.
Consider a histogram of the fraction of time in a finite length orbit originating from a typical initial point falls in N bins of equal size along the x axis.
As $N$ and orbit length $\to\infty$ this probability $\frac{1}{N}$.
Can define a Natural Invariant Density which is the fraction of time typical orbits spend in an interval [x,x+dx].
Models generational variation of population.
If infinite resources,
\[x_{n+1} = r x_n\]This is an exponential growth.
However, there must be a negative growth rate.
\[x_{n+1} = -rx_n^2\]Hence we get the logistic map.
Qualitative changes in dynamics which occur as a system parameter varies. Bifurcations are generic i
Magnitude of Stability Coefficient is 1 at bifurcation point.
For the logistic map
Solutions-
$x^* = 0 \text{ and } x^* = 1- \frac{1}{r}$. This implies $r \ge 1$ only we have 2 solutions.
For stability, examine $F’(x^*) = r-2r(x^*)^2$.
At $x=0$, $F’(0) = r$
Hence it is stable only if $r<1$.
At $x = 1-1/r$, $F’(1-1/r) = 2-r$ which is stable only if $r \in [1, 3]$