$H_1*H_2 = \iota [H_1, H_2]$
$H_3 = H_1 * H_2$ is also hermitian
$S_1 * S_2 = {S_1, S_2}$
However this is not a [01-06#Algebra] as there is no Jacobi Identity.
Set {S} with + and * defined.
Extension of c-no arithmetic.
$S = \mathbb C \cup G$
Where $\mathbb C$ is commuting, and $G$ are anticommuting, and c commutes with g. $g_1g_2 \in \mathbb{C}$. Hence, $g^2 = 0$, as $g^2 = -g^2$ and also $\in S$.
Hence, functions on $G$ are only linear.
$\zeta = \eta + i\chi$ and $\bar\zeta = \eta-i\chi$ Where $\eta, \chi$ are real Grassman numbers.
${\zeta}$ is also Grassman.
$\zeta \bar\zeta = -\bar\zeta \zeta$
Complex conjugation interchanges order of grassman #s
\((AB)^T = -B^TA^T\) \((AB)^\dagger = B^\dagger A^\dagger\)
Non empty set S and $d:S\times S\rightarrow\mathbb{R}$
For $0\in F$, $|0\rangle \in \mathbb V$, $0|v\rangle = |0\rangle$
$(0+1) |v\rangle = |v\rangle = 0|v\rangle +|v\rangle \implies 0|v\rangle = |0\rangle$
Given a set of m non-null vectors, if we can find a set of m scalars ${\alpha}$ not all zero st $\sum_{i=1}^m \alpha_i|i\rangle = |0\rangle$, then the set is called linearly dependant. Otherwise, it is Linearly independant.
$\text{dim}(\mathbb V)$ is the max number of vectors which are simultaneously independant set of vectors.
If there is no such maximum, then the dimension of V is infinity.
If $\forall\ |w\rangle \in \mathbb V \exists$ a set of scalars ${\alpha}$ st $|w\rangle = \sum_{i=1}^m \alpha_i |v_i\rangle$ is called a span of V
It is a [01-07#Span|Span] which is also [01-07#Linear Independance|Linearly Independant] is called a basis set for V.
$|v\rangle \leftrightarrow^{\text{Duality}}_{\text{Hermitian Conjugation}} \langle w|$